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Kovid Goyal 2021-01-18 16:31:09 +05:30
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docs/keyboard-protocol.rst
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@ -151,7 +151,7 @@ Modifiers are encoded as a bit field with::
In the escape code, the modifier value is encoded as a decimal number which is
``1 + actual modifiers``. So to represent :kbd:`shift` only, the value would be ``1 +
1 = 2``, to represent :kbd:`ctrl+shift` the value would be ``1 + 0b101 = 5``
1 = 2``, to represent :kbd:`ctrl+shift` the value would be ``1 + 0b101 = 6``
and so on. If the modifier field is not present in the escape code, its default
value is ``1`` which means no modifiers.